How do I apply Bernoulli's equation to a tank or nozzle problem?
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The question
My fluid mechanics assignment asks me to find the exit velocity from a tank nozzle using Bernoulli's equation.
I know the formula, but I am not sure which pressure, height and velocity terms cancel.
Short answer
To apply Bernoulli's equation, choose two points on the same streamline, state the assumptions, write pressure head, velocity head and elevation head, then solve for the unknown. For a tank draining to atmosphere, velocity often follows v = sqrt(2gh) if losses are neglected.
Full expert answer
Mechanical engineering tutor
MEng Mechanical Engineering, fluid mechanics instructor
Bernoulli's equation is one of the most common fluid mechanics tools, but students lose marks when they use it without stating assumptions. Before calculating, identify the two points, confirm they lie along a reasonable streamline, and decide which terms can be neglected. For a tank and nozzle, the usual points are the free surface in the tank and the nozzle exit.
In its head form, Bernoulli's equation is often written as:
textp1/(rho g) + v1^2/(2g) + z1 = p2/(rho g) + v2^2/(2g) + z2where pressure head, velocity head and elevation head are all in metres of fluid.
What the question is asking
The question is asking you to apply conservation of mechanical energy to fluid flow. You need to show the physical meaning of each term, not only insert numbers. A strong answer states assumptions such as steady flow, incompressible fluid, negligible viscosity or loss, and points on the same streamline.
Key concepts to cover
- Pressure head: p / rho g
- Velocity head: v squared / 2g
- Elevation head: z
- Gauge pressure versus atmospheric pressure
- Free surface velocity in a large tank
- Exit velocity from a nozzle
- Assumptions and head losses
- Units and sense check
Worked tank example
Question: A large open tank contains water. The free surface is 2.5 m above a small nozzle outlet. Estimate the exit velocity, neglecting losses.
Choose point 1 at the free surface and point 2 at the nozzle exit.
For an open tank and open nozzle, both points are exposed to atmospheric pressure, so pressure terms cancel if gauge pressure is used. The tank is large, so the free surface velocity is approximately zero. Let the nozzle exit elevation be z2 = 0, so z1 = 2.5 m.
text0 + 0 + 2.5 = 0 + v2^2/(2g) + 0
v2 = sqrt(2g x 2.5)
v2 = sqrt(2 x 9.81 x 2.5)
v2 = 7.0 m/s approximatelyThe answer is reasonable because more height gives more velocity, and the units are metres per second.
Sample questions and short answers
1. Why do atmospheric pressure terms cancel?
If both the tank surface and the nozzle exit are open to atmosphere, they have the same atmospheric pressure. Using gauge pressure, both are zero, so the pressure head terms cancel.
2. When can I ignore velocity at the tank surface?
You can usually ignore it when the tank cross-sectional area is much larger than the nozzle area. The same flow rate passes through both areas, so the large tank area makes the surface velocity very small.
3. What if the problem gives head loss?
Add the head loss term to the outlet side:
textp1/(rho g) + v1^2/(2g) + z1 = p2/(rho g) + v2^2/(2g) + z2 + hLHead loss reduces the exit velocity.
4. What assumptions should I write?
State steady, incompressible flow; negligible viscous losses unless given; points on the same streamline; and no pump or turbine work between the two points.
Common student mistakes
- Forgetting to state assumptions
- Mixing pressure in pascals with head in metres
- Using absolute pressure at one point and gauge pressure at another
- Keeping the tank surface velocity when the tank is clearly large
- Applying Bernoulli across a pump, bend, or long pipe without considering added energy or losses
- Forgetting units
How to make the answer stronger
Draw a simple diagram and label point 1, point 2, z1, z2 and the datum. Mark pressures as atmospheric if both points are open. This reduces algebra mistakes and shows the marker that your equation came from the physical system.
You can also mention limitations. Real nozzles have losses, contraction and turbulence, so measured velocity may be lower than the ideal Bernoulli estimate. In more advanced problems, use a discharge coefficient or head-loss term.
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Academic use note
This guide is for engineering assignment support. Use the method to understand your own problem, and always follow the assumptions, loss model and sign convention given by your lecturer.
Sources and further reading
This answer explains a method for you to apply to your own work. Copying it into a submission would count as plagiarism, and it is indexed by similarity checkers.
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